Factorising by grouping in pairs
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Factorising by grouping in pairs

[From: ] [author: ] [Date: 11-08-05] [Hit: ]
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How with you factorise these expressions?

1) x^3 - 2x^2 - xy + xz - 2z +2y

2) 2x^2 + 2xy + xz + xz^2 + yz +yz^2

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Rearrange to x^3-2x^2 -xy + 2y + xz -2z

Make 3 groups, factor common factors

x^2(x-2) -y(x-2) +z(x-2)

Factor out (x-2)

(x-2)(x^2-y+z)


To see how I need to rearrange, just make the first group

2x(x+y)

Which means the rest must have an x and y as well as a common factor

2x(x+y) +xz+ yz + xz^2 + yz^2

2x(x+y) + z(x+y) + z^2(x+y)

(x+y)(2x+z+z^2)
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