If the bullet has a mass of 29.0 g and a speed of 550 m/s, how high will the block rise after the bullet becomes embedded in it?
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Momentum of bullet will be transfered to the block of wood.
m1v1=m2v2
0.029*550=1.4v2
v2=0.029*550/1.4=11.4m/s.
v²=u²+2ax
(11.4)²=2(9.81)(x)
130=19.62x
x=6.6m (approx).
m1v1=m2v2
0.029*550=1.4v2
v2=0.029*550/1.4=11.4m/s.
v²=u²+2ax
(11.4)²=2(9.81)(x)
130=19.62x
x=6.6m (approx).
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equate momentum of bullet to momentum of the block at rest. =)