The rectangle has a width of 6 inches less than 4 times it length.
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w=4L-6
A=l(4l-6)
A=4L^2 -6L
A= 2L(2L-3)
get rid of w
A=l(4l-6)
A=4L^2 -6L
A= 2L(2L-3)
get rid of w
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Come up with an expression for the area.
Let's call the length L, and the width w.
4L-6 = w.
Area = L*w = L*(4L-6) = 4L^2 - 6L.
Now you have an expression of the area only in terms of the length, L. Coming up with algebraic expressions based on prose is a difficult but powerful skill.
Let's call the length L, and the width w.
4L-6 = w.
Area = L*w = L*(4L-6) = 4L^2 - 6L.
Now you have an expression of the area only in terms of the length, L. Coming up with algebraic expressions based on prose is a difficult but powerful skill.