Inequality When It Is < 1/10

Solve the inequality and write answer in interval notation.

|3(x + 2)^2 - 3x^2| < 1/10

|3(x+2)²-3x²|<1/10

|3x²+12x-12-3x²|<1/10

|12x+12|<1/10

12|x+1|<1/10

|x+1|<1/120

-1/120<(x+1)<1/120

-121/120
(-121/120,-119/120)

|3x^2 + 12x + 12 - 3x^2| < 1/10

|12x + 12| < 1/10

12|x + 1| < 1/10

|x + 1| < 1/120

x + 1 < 1/120 ---> x < 1/120 - 1 ---> x < - 119/120
AND
x + 1 > - 1/120 --> x > - 1/120 - 1 --> x > - 121/120

- 121/120 < x < - 119/120

(- 121/120, - 119/120)