In one hand you hold a 0.15- kg apple, in the other hand a 0.24- kg orange. The apple and orange are separated by 0.86 m.
a.) What is the magnitude of the force of gravity that the orange exerts on the apple?
b.) What is the magnitude of the force of gravity that the apple exerts on the orange?
a.) What is the magnitude of the force of gravity that the orange exerts on the apple?
b.) What is the magnitude of the force of gravity that the apple exerts on the orange?
-
Hey Esmeralda,
Use Newton's law of gravitation:
F=GMm/r^2, where G is a constant of value 6.67e-11, M and m are the masses of the objects, and r is the distance separating them. Now, let's calculate the force:
F=(6.67e-11)(.15)(.24)/(.86)^2=3.2e-12 N. This answer is the same of both the orange and apple because of Newton's third law, which states:
The mutual forces of action between two bodies are equal, opposite, and collinear.
Does this help?
David
Use Newton's law of gravitation:
F=GMm/r^2, where G is a constant of value 6.67e-11, M and m are the masses of the objects, and r is the distance separating them. Now, let's calculate the force:
F=(6.67e-11)(.15)(.24)/(.86)^2=3.2e-12 N. This answer is the same of both the orange and apple because of Newton's third law, which states:
The mutual forces of action between two bodies are equal, opposite, and collinear.
Does this help?
David
-
you are given m1, m2 and r
so look up G
and solve this
F = G (m1*m2) / r^2
then
a and b both equal F (action/reaction)
so look up G
and solve this
F = G (m1*m2) / r^2
then
a and b both equal F (action/reaction)