Help?! Z[sqrt2]={a+b sqrt 2| a, b in Z} Z[sqrt3]={a+b sqrt 3| a, b in Z} Prove that Z[sqrt2]∩Z[sqrt3]=Z

A+BSQRT2=C+DSQRT3==>A-C = DSQRT3-BSQRT2 is irrational
unless D=B=0. Therefore Z[SQRT2] andZ[SQRT3] only have the
integers in common and this happens when D=B=0 for all D and B.