If the probability that a certain tennis player will serve an ace is 3/14, what is the probability that he will serve exactly 3 aces out of 8 serves?
I believe 0.005892 is the answer but not right apparently...
Thank you in advance
I believe 0.005892 is the answer but not right apparently...
Thank you in advance
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This is a binomial distribution:
P(exactly 3 aces out of 8 serves)
= C(8,3) * (3/14)^3 * (11/14)^5
= 56 * (3/14)^3 * (11/14)^5
= 0.165002655
Your answer seems to be 2 * (3/14)^3 * (11/14)^5
Not sure where you got 2 from?
P(exactly 3 aces out of 8 serves)
= C(8,3) * (3/14)^3 * (11/14)^5
= 56 * (3/14)^3 * (11/14)^5
= 0.165002655
Your answer seems to be 2 * (3/14)^3 * (11/14)^5
Not sure where you got 2 from?
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The probability of exactly 3 aces, also means exactly 5 non aces in 8 serves
(3/14)^3 (11/14)^5 = .002946476
(3/14)^3 (11/14)^5 = .002946476