A tuning fork oscillates at a frequency of 656 Hz. Find the period of the motion.
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T = 1/f
So period is 1/656 = 0.0015seconds
1.5 milliseconds.
So period is 1/656 = 0.0015seconds
1.5 milliseconds.
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Period = T
T= 1/ Frequency
T= 1/ 656
T= 0.0015
T= 1/ Frequency
T= 1/ 656
T= 0.0015