Physics Static Equilibrium

I have tried everything and I'm completely stumped. Please help me out.

A 15310 N automobile has a wheel base (the distance between the axles) of 3.10 m. The center of mass of the automobile is on the center line at a point 1.50 m behind the front axle. Find the force exerted by the ground on each wheel.

Lets assume that the front axel is to the left.
As the center of mass is on the center line of the car left to right, then each front wheel will carry identical loads and each back wheel will carry identical loads, but not the same load as the front wheels.

If we sum moments about the front wheel to ground contact point, the front wheel forces have no moment arm and thus create no moment.
If we assume that clockwise is the positive direction, then the car mass will create a positive moment and the reaction forces at the rear wheels will create a negative moment

mg(1.5) - Fr(3.1) = 0
Fr = 15310(1.5) / 3.1
Fr = 7408

so each rear tire will carry half that load
7408 / 2 = 3704 N

The front tires will carry the remaining loads
15310 - 7408 = 7902 N

and each front tire will carry half the remaining load
7902 / 2 = 3951 N