Luther decides to try and drop a water balloon on his brother from a 25 story balcony. If air resistance can be ignored the balloon is released from 100 m above ground from rest, what speed will it have traveled when it reaches the 50 m mark above the ground? What is the speed when it reaches the ground?
And if you dont mind this question too
A ball is dropped from rest at a height of 150 m above a canyon. If the mass of the ball is 1.35kg, what is its initial energy?
thanks you all so much
And if you dont mind this question too
A ball is dropped from rest at a height of 150 m above a canyon. If the mass of the ball is 1.35kg, what is its initial energy?
thanks you all so much
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Use potential energy = kinetic energy
mgh = (1/2)mv^2
The m's cancel
gh = (1/2)v^2
solve for v using h1 and h2
With the second one, it's simply mgh
mgh = (1/2)mv^2
The m's cancel
gh = (1/2)v^2
solve for v using h1 and h2
With the second one, it's simply mgh