(please walk me thru this) in a certain fraction,the denominator is 6 more than the numerator. if 3 is added to both the numerator and the denominator, the resulting fraction is equivalent to 5/7. what was the original fraction?
let n=the numerator
then n+6 denominator
n+3 = 5
--------- -----
n+6+3= 7
let n=the numerator
then n+6 denominator
n+3 = 5
--------- -----
n+6+3= 7
-
Hello
If two fractions are equal, make the cross product !
Example if a/b = c/d, then ad = bc
Here 7(n+3) = 5(n+9)
7n + 21 = 5n + 45
7n - 5n = 45 - 21
2n = 24
n = 12
The original fraction was 12/18
If you add 3 you have 15/21 = 5/7
Hope it helps
Bye !
If two fractions are equal, make the cross product !
Example if a/b = c/d, then ad = bc
Here 7(n+3) = 5(n+9)
7n + 21 = 5n + 45
7n - 5n = 45 - 21
2n = 24
n = 12
The original fraction was 12/18
If you add 3 you have 15/21 = 5/7
Hope it helps
Bye !