How do you solve this problem? thanks!
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How do you solve this problem? thanks!

[From: ] [author: ] [Date: 12-04-12] [Hit: ]
percent of all students had scores less than 820?z for 0= -4.z for 820= -0.The integral of the Prob. Den. Fnc.......
The National Collegiate Athletic Association (NCAA) requires division
I athletes to score at least 820 on the combined mathematical
and verbal parts of the SAT exam to compete their first college year.
(Higher scores are required for students with poor high school grades.)
In 2002, the scores of the 1.3 million students taking the SATs were approximately
normal with mean 1020 and standard deviation 207. What
percent of all students had scores less than 820?

-
The z-value is (value - mean)/sigma
Mean = 1020 : Sigma = 207
z for 0 = -4.92753623188406
z for 820 = -0.966183574879227
The integral of the Prob. Den. Fnc. From -4.92753623188406 to -0.966183574879227 is
p(-4.92753623188406, -0.966183574879227) = 0.16698
or 16.7%
you may need to use a table to look these up if your calculator doesn't do this.
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