F= 9C/5 +32
Can you give me the steps and logic to the subject of C please?
Can you give me the steps and logic to the subject of C please?
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When working with equations you have to do the same to both sides of what you do to one side.
F= 9C/5 +32
x5 5F=9C+32 x5
-32 5F-32=9C -32
divide by 9 5F-32 divided by/over 9 =C divide by 9
Answer : C=5F-32 divided by/over 9
F= 9C/5 +32
x5 5F=9C+32 x5
-32 5F-32=9C -32
divide by 9 5F-32 divided by/over 9 =C divide by 9
Answer : C=5F-32 divided by/over 9
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Multiply 5 to all terms
Subtract 32 both sides
(9/5)C = F - 32
Multiply 5 both sides
9C = 5(F - 32)
Divide 9
C = (5/9)(F - 32)
Subtract 32 both sides
(9/5)C = F - 32
Multiply 5 both sides
9C = 5(F - 32)
Divide 9
C = (5/9)(F - 32)