Can you help me with my Pre-Calculus math problems

1.) Solve for "X"
log (x2-1) = 2

2.)log x 8 = -1

Thank you!!

Lacee -

I'm going to have to sort of guess at your symbols ...

(1) log[x^2 - 1] = 2, now raise both sides by 10

10^{log[x^2 - 1]} = 10^2 = 100, now the left side will simplify to:

x^2 - 1 = 100

x^2 = 101

x = +/- sqrt 101 = approx +/- 10.05

(2) log x^8 = -1

same procedure raise both sides by 10

10 ^ { log x^8] = 10^-1 = 1/10

x^8 = 1/10

x = +/- (1/10) ^(1/8) = approx. +/- 0.75

Hope that helps