Fluid density physics problem

You need to determine the density of a ceramic statue. If you suspend it from a spring scale, the scale reads 36.2 N. If you then lower the statue into a tub of water, so that it is completely submerged, the scale reads 12.2 N. What is the density? (In kg/m^3)

I tried solving for buoyancy to get volume (.00124). Then using F=mg to with the 36.2 N to find m. 'But when I plugged it into the d=m/v equation I got 2967.21 kg/m^3

Help please, not sure where I'm going wrong

Yes, you need to get volume solving for buoyancy but you need to check your calculations.
I will call buoyancy force, F_b. so
36.2-12.2=24N
F_b=24N

F_b=V_b*d_liquid*g
since the liquid is water the density (you can find off the tables) is 997kg/m^3 (at 25C)
also it is completely submerged so V_b (buoyancy volume) is equal to V.
24=V*997*9.81
Solving V in this equation gave me 0.002454 and its units is m^3

Density is mass divided by volume.
d=m/V
you can find mass from the weight
W=36.2=m*g
36.2=m*9.81
m=3.69kg

d=3.69/0.002454
d=1503.7 kg/m^3

(36.2 - 12.2) = water weight of 24N. displaced.
24N = (24/9.8) = 2.44898kg. of water.
Volume displaced = 2.44898 litre, which is 2,448.98cc.
(36.2/9.8) = 3.6938kg., which is 3,693.8g.
Density = (3,693.8/2,448.98) = 1.508g/cc., or 1,508kg/m^3.