Pre-calculus problem
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Pre-calculus problem

[From: ] [author: ] [Date: 12-04-12] [Hit: ]
x = -3, 3, -1,2) The fundamental theorem of algebra tells you that a cubic polynomial has three zeros.(In this particular case, only one of them is real.......
Needed help with this equation.
g(x)=1/5(x^4-10x^2+9)

a) Factor g(x) completely
b) Find x-intercept(s) for g(x)
c)Find y-intercept for g(x)

2) Given polynomial function f(x)=x^3-7x^2+24x-28
How many zeros (or roots) does f(x) have?

Thanks

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a)
g(x) = 1/5 (x^2 - 9) (x^2 - 1) = 1/5 (x + 3) (x - 3) (x + 1) (x - 1)

b) Use the zero product principle four times:
x = -3, 3, -1, 1

c)
g(0) = 9/5

2) The fundamental theorem of algebra tells you that a cubic polynomial has three zeros. (In this particular case, only one of them is real.)
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