Can anyone list me all the kinematics equations?I will vote for the best answer.Thanks in advance and wish you have a happy new year!!!
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KINEMATICS EQUATIONS
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For Linear Motion
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CASE I : For acceleration = 0 m/s^2
> distance = speed x time [ d = s x t ]
Now rearranging this equation, we have,
> speed = distance / time [ s = d/t ]
> time = distance / speed [ t = d/s ]
CASE II: For uniform acceleration
> v = u + at [ 1st equation of motion ]
> h = ut + 1/2 x a x t^2 [ 2nd Equation of motion ]
> v^2 = u^2 + 2ah [ 3rd Equation of motion ]
where, u = initial velocity, v = final velocity, t = time taken, h = distance traversed, a = acceleration
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For Circular Motion
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> length of arc traversed = radius x (theta) [s = r θ]
Note that (theta) i.e. the angle must be in radians.
> angular speed = (2 x pi x radius) / (time taken) [ ω = 2πR / t ]
= (angular displacement) / (time) [Δθ / Δt]
> tangential speed = angular speed x radius [ v = ω x r ]
= arc of circle traversed / time [ v = ds / dt ]
> radial acceleration = (tangential velocity)^2 / (radius) [ α = v^2 / r ]
= (angular velocity)^2 x radius [ α = ω^2 x r ]
Also called "CENTRIPETAL ACCELERATION"
[Extra Point:Corresponding Force [Centripetal force] = mα = m(v^2 / r)
> tangential acceleration = angular acceleration x radius [ a = α x r ]
= tangential velocity / time [ a = dv / dt ]
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If angular acceleration is uniform,
> θ = [(ω1) x t] + [1/2 x α x t^2] (just like h = ut + 1/2 at^2)
> ω2 = ω1 + αt (just like v = u + at)
> (ω2)^2 - (ω1)^2 = 2αθ (just like v^2 - u^2 = 2aS)
where, θ = angular displacement
ω1 = Initial angular velocity
ω2 = final angular velocity
α = angular acceleration
================================
--------------------------------------…
For Linear Motion
--------------------------------------…
CASE I : For acceleration = 0 m/s^2
> distance = speed x time [ d = s x t ]
Now rearranging this equation, we have,
> speed = distance / time [ s = d/t ]
> time = distance / speed [ t = d/s ]
CASE II: For uniform acceleration
> v = u + at [ 1st equation of motion ]
> h = ut + 1/2 x a x t^2 [ 2nd Equation of motion ]
> v^2 = u^2 + 2ah [ 3rd Equation of motion ]
where, u = initial velocity, v = final velocity, t = time taken, h = distance traversed, a = acceleration
--------------------------------------…
For Circular Motion
--------------------------------------…
> length of arc traversed = radius x (theta) [s = r θ]
Note that (theta) i.e. the angle must be in radians.
> angular speed = (2 x pi x radius) / (time taken) [ ω = 2πR / t ]
= (angular displacement) / (time) [Δθ / Δt]
> tangential speed = angular speed x radius [ v = ω x r ]
= arc of circle traversed / time [ v = ds / dt ]
> radial acceleration = (tangential velocity)^2 / (radius) [ α = v^2 / r ]
= (angular velocity)^2 x radius [ α = ω^2 x r ]
Also called "CENTRIPETAL ACCELERATION"
[Extra Point:Corresponding Force [Centripetal force] = mα = m(v^2 / r)
> tangential acceleration = angular acceleration x radius [ a = α x r ]
= tangential velocity / time [ a = dv / dt ]
--------------------------------------…
If angular acceleration is uniform,
> θ = [(ω1) x t] + [1/2 x α x t^2] (just like h = ut + 1/2 at^2)
> ω2 = ω1 + αt (just like v = u + at)
> (ω2)^2 - (ω1)^2 = 2αθ (just like v^2 - u^2 = 2aS)
where, θ = angular displacement
ω1 = Initial angular velocity
ω2 = final angular velocity
α = angular acceleration
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The ones you ought to know are:
The SUVAT equations... So
v = u + at
v^2 = u^2 = 2as
s = ut + at^2/2
v = s/t
Then:
A = dv/dt
F = ma
W = Fd
P= Fv = W/t
KE = mv^2/2
GPE = mgh
And then a rearrangement or rather the original version...
Fdt = mdv...
And then conservation of momentum...
m1v1 + m2v2 = v(m1+m2)
I think that that is about it...
The SUVAT equations... So
v = u + at
v^2 = u^2 = 2as
s = ut + at^2/2
v = s/t
Then:
A = dv/dt
F = ma
W = Fd
P= Fv = W/t
KE = mv^2/2
GPE = mgh
And then a rearrangement or rather the original version...
Fdt = mdv...
And then conservation of momentum...
m1v1 + m2v2 = v(m1+m2)
I think that that is about it...