Need help with radicals as exponents

the specific questions is:

3^(1 - 2Y) = rad(3)

(1-2Y)=1/2
-2Y=-1/2
Y=1/4
God bless you.

3^(1 - 2y) = √3

square both sides

[3^(1 - 2y)]^2 = 3

3^(2 - 4y) = 3^1

2 - 4y = 1
1 = 4y
1/4 = y

3^(1 - 2(1/4)) = √3

3^(1 - 1/2) = √3

3^(1/2) = √3

true

3^(1 - 2y) = 3^(1/2)
1 - 2y = 1/2
1/2 = 2y
y = 1/4