Two charged particles attract each other with a force F. If the charges of both particles are doubled, and the distance between them also doubled, then the force of attraction will be
A) F.
B) 2 F.
C) F/2.
D) F/4.
E) none of these
Please, explain in detail
Thank you
A) F.
B) 2 F.
C) F/2.
D) F/4.
E) none of these
Please, explain in detail
Thank you
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the force between two charged particles is
F = k q1 q2/r^2
k is a constant
q1, q2 are the magnitudes of the charges
r is the separation of the charges
if you double each charge, the force increases by a factor of 2 x 2 =4
if you double the distance, the force decreases by a factor of 1/2^2 = 1/4
the combination of these factors is 4 x 1/4 = 1, meaning the force is unchanged, and the correct answer is A
F = k q1 q2/r^2
k is a constant
q1, q2 are the magnitudes of the charges
r is the separation of the charges
if you double each charge, the force increases by a factor of 2 x 2 =4
if you double the distance, the force decreases by a factor of 1/2^2 = 1/4
the combination of these factors is 4 x 1/4 = 1, meaning the force is unchanged, and the correct answer is A
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If the charges are doubled, then the force becomes 4F. The distance is doubled, and that divides the force by 4, taking it back to F.
Remember: F=k Qq/r^2
Remember: F=k Qq/r^2