A system has a total pressure of 2.3atm and Volume of 11.2 L at 298K. there are two gases present in this syst

I NEED HELP!!!! :)

you need to use the ideal gas law pv=nrt to find the total moles in the system, so you are solving for n. r is a constant .

In the end you should get 1.053 moles total.

using the information given;Gas A partial pressure 1.5atm you can calculate the amount of moles present of gas A, then you will just substract Total amount-amount A= amount B

use partial pressure and mole fraction equation(from daltons law)
xa=na/ntotal n=moles solve for na.
pa=xa*ptotal pa=partial pressure. solve for xa. use info given.

1.053-0.69=0.366 moles of gas B. hope it helps

you calculate this from Dalton's law

p(B)= p(total) - p(A)= 0,8 atm

p(B)= p(total) * y(B)

y(B)= p(B)/p(total)= 0,8 atm / 2,3 atm= 0,35

y(A)= p(A)/p(total)= 1,5 atm / 2,3 atm= 0,65

y(A)= n(A)/(n(A) + n(B))

y(B)= n(B)/(n(B) + n(A))

and now you can see you are missing one information and that is number of moles of A or y(A) or y(B)

;)