Answer above is correct but here is an explanation
base 10 works with powers of 10 from right to left (10^0, 10^1, 10^2) creating the ones place, tens place, and hundreds and so on
the same is for base 12 (12^0, 12^1) so you look for how many 12^1's can go into 37 which is 3 and then how many 12^0s go into it which is 1
result being 31
base 10 works with powers of 10 from right to left (10^0, 10^1, 10^2) creating the ones place, tens place, and hundreds and so on
the same is for base 12 (12^0, 12^1) so you look for how many 12^1's can go into 37 which is 3 and then how many 12^0s go into it which is 1
result being 31
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37 to base 12.
Divide 37 by 12. You should get 3. So your first digit is 3.
What is the remainder? 3*12 = 36. 37 - 36 = 1
So 37(base 10) = 31(base 12)
Think of how we represent numbers in base 10. Divide by the largest power of 10 and start keeping the remainder for the later digits.
Divide 37 by 12. You should get 3. So your first digit is 3.
What is the remainder? 3*12 = 36. 37 - 36 = 1
So 37(base 10) = 31(base 12)
Think of how we represent numbers in base 10. Divide by the largest power of 10 and start keeping the remainder for the later digits.
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37=31 base 12 means 3(12)^1+1(12)^0
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3 • 12 = 36
37 – 36 = 1
37_10 = 31_12
37 – 36 = 1
37_10 = 31_12
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God is your name pritty than your face
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Since 37 is 3 x12 +1 =31
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37 = 12^1,453140267