If y= 1-x/2x +1, then dy/dx =

Derivative Question

y= (1-x) / (2x +1)

dy/dx =[ (2x +1) (-1) - (1-x) (2) ] / (2x +1)^2

= [ -2x -1 - 2 + 2x ] / (2x +1)^2

= -3 / (2x +1)^2

answer

agree w/tbt. use quotient rule

y' = -3/(2x+1)^2

y= (1-x)/2x +1,
y'=[(2x)(-1)-(1-x)(2)/(2x)²
y'=(-2x+2x-2)/4x²
y'=(-1/2x²)