Stats isnt really my thing, any help is appreciated
1. Assume that head sizes (circumference) of new recruits in the Canadian armed forces can be
approximated by a normal distribution with a mean of
I know the answer is 1/12, but how do I get the answer? Could someone please explain it or show it? thank you.-the answer is indeed 1/12. probability is the ratio of the number of ways to get the desi
Group G = {1,-1,i,-i} where i^2 = -1
Group a = {[0],[1],[2],[3]}
Group b = {([0].[0]),([0],[1]),([1],[0]),([1],[1])…
From my Cayley table, I came up with the answer that G and a are isomorphic and G
1) P is a point on an edge of a circle, centre O.
The line PQ is the tangent to the circle at P.
R is the point on OQ such that angle ORP = 90 degrees.
a) Prove that triangle QPR and triangle OPQ are
Hi, here is just 2 questions of many, but i need to know the basics. Can you please answer and show working fully of these questions:
The question is:
Differentiate each of these functions with respe
I get y = -x/y as the derivative but cant figure out what to do next
1. Consider the circle x^2+y^2 = 1.
(a) At what point(s) is the slope of the tangent line equal to 1?
(b) At what point(s) is the
Equation is 10x^2 -7x + 1 = 0
x = ______ or _________
you have to factor and use quadratic formula, Im so confused and would appreciate it very much if somebody can do this one problem for me so I c
How can I find the derivative of f(x)=e^(1/x^2) from first principles (ie limit as h->0)?-1) f(x) = e^(1/x²); ==> f(x+h) = e^{1/(x+h)²}
2) So, f(x+h) - f(x) = e^{1/(x+h)²} - e^(1/x²) = e^(1/x²)[e^{1/
A little lost at how i can tackle the question. any help would be appreciated.
Find the stationary points of the function y=(x^2+1)/x and test them for their nature.
Please show all workings-y = x + x
Need help verfying... csc(-x)-sin(-x)=-cosxcotx
sin^2x(1+cot^2x)=1-For the first identity:
From a knowledge of the Law of Quadrants or by testing on your calculator
sin (-x) = - sin (x)
cosec (-x) = 1
help??--3 and -16-let x & y be the two nmbers.
xy = 48 ............ equation (1)
x + y = –19
y = –x - 19 ............... equation (2)
plug in value of y in eq (2) into eq (1);
x ( –x - 19 ) = 48
–x
