∫C xydx+(x-y)dy; C is from (0,0) to (2,0) and (2,0) to (3,2).
I look at this and I dont even know where to start.-Break C into two segments:
(i) (0, 0) to (2, 0) via x = 2t, y = 0 for t in [0, 1].
http://imageshack.us/photo/my-images/841/integrales2.png/-Integrating 85*x*cos(170*x) I get:
(170*x*sin(170*x)+cos(170*x))/340
Integrating x*sin(85*x) I get
(sin(85*x)-85*x*cos(85*x))/7225
Hope it hel
1.(x^5)^10
2.18a^4/3a^2
3.12/16 in simplest form-assuming expression is
(x^5) ^ 10
law of exponents; to the power of apower, multiply the exponents
x^(5 times 10)
x^50
assuming expression i
P and Q are integers that between them contain each of the digits from 0 to 9 once and only once. What is the maximum value of P x Q?-96420 x 87531 = 8439739020
You want the numbers to be roughly equ
Form a polynomial f(x) with real coefficients having the given degree and zeros.
Degree: 4; Zeros: -4+2i; -3 multiplicity 2.
It asks me to enter the polynomial.
I got this...f(x) = a(x^4-2x^3-19x^2+
And can you please show how you got your answer ?
Thank You xXx-When you have a fraction raised to a - power, the rule is flip the fraction and write the power as a +
(5/6)^1-Power of -1 gives you 1
I need help solving this. I just cant figure it out. [(4/ab)-(3/b^2)]/[(5/a)(3/b^2)]-Step 1: Use rules for adding and subtracting fractions to find a simpler expression for the numerator.
4/(ab) - 3/(
can someone check these calculations for me please?
if i use 4 kwh of electricity per day and my energy company charges 19p for the first 225 units over three months and 10p per unit after that, roun
1. Solve for c.ab - c = 9
A. -ab - 9
B. 9 + ab
C. ab - 9
2. Find two consecutive integers whose sum is 73.
Which of the following equations could be used to solve the problem?
A. 2x = 73
B. 2x + 1 =
1. Find the thirtieth term of the following sequence.
-6, -4, -2, 0, ...
A. 52
B. 64
C. 66
2. Given: y varies directly with x and has a constant rate of change of 7.
When the value of y is 12, then t
in which each element from A is associated with exactly one element from B and no two elements of A are paired up with the same element of B. In this pairing, however, there are elements of B that are
http://www.admissionstests.cambridgeasse…
question 20 please
i tried to re-arrange and such, but could not do it
any help is much appreciated-answer is A
volume = πr²h
area = 2πr² + 2πrh
volume =
Given the curves r=2sin(x) and r=2sin(2x), 0=x=pi/2, find the area of the region outside the first curve and inside the second curve.-r=2sin x
r=2sin2x
they cut when 2sinx=2sin2x
sinx=sin2x
sinx= 2s
0 = 6x^2 + 512 / x
Wheres my mistake?
-512 / x = 6x^2
-512 = 6x^3
-512 / 6 = x^3
(-512 / 6)^(1/3) = x
4.40 = x
Note, the answer must be positive because were dealing with square feet.
Heres the or
