Hi, here is just 2 questions of many, but i need to know the basics. Can you please answer and show working fully of these questions:
The question is:
Differentiate each of these functions with respect to x, to find F'(x).
1. F(x)= x^2-6x+8
2. F(x)= 4x^4-3x^2+7x+5
Many Thanks
The question is:
Differentiate each of these functions with respect to x, to find F'(x).
1. F(x)= x^2-6x+8
2. F(x)= 4x^4-3x^2+7x+5
Many Thanks
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If you have a function like f(x) = ax^b...then the differentiation is f ' (x) = (b)(a)x^(b-1)...
If f(x) = c, where c is constant, then the differentiation is always zero.
For 1)
f(x) = 1x^2 - 6x + 8
f ' (x) = (2)(1)x^(2-1) - (1)(6)x^(1-1) + 0 = 2x - 6
For 2)
f(x) = 4x^4 - 3x^2 + 7x + 5
f ' (x) = (4)(4)x^(4-1) - (2)(3)x^(2-1) + (1)(7)x^(1-1) + 0 = 16x^3 -6x + 7
If f(x) = c, where c is constant, then the differentiation is always zero.
For 1)
f(x) = 1x^2 - 6x + 8
f ' (x) = (2)(1)x^(2-1) - (1)(6)x^(1-1) + 0 = 2x - 6
For 2)
f(x) = 4x^4 - 3x^2 + 7x + 5
f ' (x) = (4)(4)x^(4-1) - (2)(3)x^(2-1) + (1)(7)x^(1-1) + 0 = 16x^3 -6x + 7
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{x^2 - 6 x + 8,
4 x^4 - 3 x^2 + 7 x + 5}
{-6 + 2 x,
7 - 6 x + 16 x^3}
4 x^4 - 3 x^2 + 7 x + 5}
{-6 + 2 x,
7 - 6 x + 16 x^3}