2 numbers that multiply to 48 and add to -19

help??

-3 and -16

let x & y be the two nmbers.

xy = 48 ............ equation (1)

x + y = –19
y = –x - 19 ............... equation (2)

plug in value of y in eq (2) into eq (1);
x ( –x - 19 ) = 48
–x ² - 19x = 48
x ² + 19x + 48 = 0
( x + 16 ) ( x + 3 ) = 0
x + 16 = 0 ............... & ................ x + 3 = 0
x = –16 ............... & ................ x = –3
░░░░░░░░░░░░░░░░░░░░░░░░░

x + y = -19
xy = 48
x + 48/x = - 19
x ² + 48 = - 19x
x ² + 19x + 48 = 0
( x + 16)(x + 3) = 0
x = - 16
y = - 3
is acceptable answer

x+y = -19
or y = -19 - x
xy = 48
substitute for y
x (-19-x) = 48
-x^2 - 19x - 48 = 0
x^2 + 19x + 48 = 0
(x+16)(x+3) = 0
x = -16
x = -3