What do they want for this math problem and how do I solve it

5(12-3p) = 15p+60

First you distribute the 5:
(5 x 12) - (5 x 3p) = 15p + 60
60 - 15p = 15p + 60

Then you get the variable all on one side and the non-variable all on one side:
60 - 15p + 15p = 15p + 60 + 15p
60 = 30p + 60
60 - 60 = 30p + 60 - 60
0 = 30p

Obviously, p=0. However, if you want to finish it off mathematically, you divide both sides by 30 to get the variable all by itself:
0/30 = 30p/30
0 = p

5(12-3p) = 15p+60

Solve for p.

Expand the bracket:

60-15p =15p+60

Arrange like terms:

-15p-15p =60-60

-30p =0

p= 0

[check by substituting value for p in original equation.]

what do they want for this math problem and how do I solve it?
5(12-3p) = 15p+60

,,.'they' want you to find a value for " p " that makes the equation TRUE !

In other words, solve for p:

distribute...
60 - 15p = 15p + 60

30p = 0

p = 0

check

¶

5(12-3p) = 15p+60
60 - 15p = 15p + 60
-15p - 15p = 60 - 60
- 30p = 0
p = 0 answer//

50 - 15p = 15p + 60
-10 = 30p
p = -1/3