A 0.405 g sample of KHP is dissolved in 50 ml of water. The sample is then titrated with 15.50 ml of NaOH solution. What is the molar concentration of the NaOH solution?
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KHP and NaOH react in equimolar amounts.
(0.405 g KHP) / (204.22 g KHP/mol) / (0.01550 L) = 0.128 M NaOH
The 50 ml of water is not significant.
(0.405 g KHP) / (204.22 g KHP/mol) / (0.01550 L) = 0.128 M NaOH
The 50 ml of water is not significant.