P4(s) + 5O2(g) -----> P4O10(s)
How many grams of phosphorus react with 6.599 x 101 L of oxygen (O2) at STP (standard temperature and pressure) to form tetraphosphorus decaoxide?
How many grams of phosphorus react with 6.599 x 101 L of oxygen (O2) at STP (standard temperature and pressure) to form tetraphosphorus decaoxide?
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What volume of O2 do you mean?
6.599*101 = 666.499 L - but I am sure that this is not what you want .
I will guess that you are asking about 65.9 L
At STP, 1mol = 22.4L
65.9L = 65.9/22.4 = 2.942 mol O2
1mol P4 reacts with 5 mol O2
2.942/5 = 0.588 mol P4 reacts with 2.942 mol O2
Molar mass P4 = 30.974*4 = 123.896g/mol
0.588 mol = 0.588*123.896 = 72.85g P4 required.
6.599*101 = 666.499 L - but I am sure that this is not what you want .
I will guess that you are asking about 65.9 L
At STP, 1mol = 22.4L
65.9L = 65.9/22.4 = 2.942 mol O2
1mol P4 reacts with 5 mol O2
2.942/5 = 0.588 mol P4 reacts with 2.942 mol O2
Molar mass P4 = 30.974*4 = 123.896g/mol
0.588 mol = 0.588*123.896 = 72.85g P4 required.