i really do not know how to do this? Can you please explain me how to do it?
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first you have to realize the relationship between temperature and volume:
as you heat a sample of gas you will cause more rapid motion of the gas atoms and cause them to expand and take up more space (as you INCREASE heat you INCREASE volume)
so we can say they are proportional, so if you decrease one the other will decrease as well
note: you must convert temperature from degrees celsius to Kelvin (add 273 to each)
when variables are proportional we can write them as a proportion (or a fraction):
V/T
*now we are going to compare a volume of gas at one temp to find an unknown volume at a different temp*
we will use the same proportions but now make them equal since as one variable changes the unknown variable will change at the same rate:
V1/T1 = V2/T2
V1 and T1 are our original variables that we know and V2 will be the new unknown volume and T2 will be the new temperature
if we rearrange the equation first we can then make it easier to solve for the new volume without having numbers to mess with
*lets multiple both sides by T2 to allow T2 to cancel on the right and leave just V2
T2(V1/T1) = (V2/T2)T2
T2(V1/T1) = V2
298(250/340.8) = V2 = 218 L
so you notice we decreased the temperature and we also decreased the volume :)
as you heat a sample of gas you will cause more rapid motion of the gas atoms and cause them to expand and take up more space (as you INCREASE heat you INCREASE volume)
so we can say they are proportional, so if you decrease one the other will decrease as well
note: you must convert temperature from degrees celsius to Kelvin (add 273 to each)
when variables are proportional we can write them as a proportion (or a fraction):
V/T
*now we are going to compare a volume of gas at one temp to find an unknown volume at a different temp*
we will use the same proportions but now make them equal since as one variable changes the unknown variable will change at the same rate:
V1/T1 = V2/T2
V1 and T1 are our original variables that we know and V2 will be the new unknown volume and T2 will be the new temperature
if we rearrange the equation first we can then make it easier to solve for the new volume without having numbers to mess with
*lets multiple both sides by T2 to allow T2 to cancel on the right and leave just V2
T2(V1/T1) = (V2/T2)T2
T2(V1/T1) = V2
298(250/340.8) = V2 = 218 L
so you notice we decreased the temperature and we also decreased the volume :)