For IB Chemistry HL, I have to prepare an experiment in which i create 1 gram of a precipitate using an ionic reaction.
However i have NO IDEA what I could use to do that.
Please keep in mind that my school doesn't have many chemicals, so please help me find an experiment done with common substances.
I will also need help in explaining how I will create 1 gram of the precipitate!
I need an answer ASAP, so whoever gives me a simple, complete, detailed answer and (another option, just in case) first gets best answer! Thanks =)
However i have NO IDEA what I could use to do that.
Please keep in mind that my school doesn't have many chemicals, so please help me find an experiment done with common substances.
I will also need help in explaining how I will create 1 gram of the precipitate!
I need an answer ASAP, so whoever gives me a simple, complete, detailed answer and (another option, just in case) first gets best answer! Thanks =)
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Na2SO4 + BaCl2 = BaSO4 (precipitate) + 2 NaCl or sodium sulfate plus barium chloride = barium sulfate plus sodium chloride
You just have to mix the two solutions (keep in mind that BaCl2 is toxic when ingested)
142.04 g Na2SO4 and 208,23 g BaCl2 yield 233.43 g BaSO4, so to obtain 1 g, you'll have to mix solutions that contain 0.608 (or 142.04/233.43) g Na2SO4 and 0.892 (or 208,23/233,43) g BaCl2. Please keep in mind that the dry salts may be hydrates (i.e. contain additional water), and then you have to recalculate the weights that you need.
As for limiting and excess reagents - if you add twice more Na2SO4 than given above to the amount of BaCl2 given above, you won't obtain 2 g of precipitate, and baCl2 is the limiting reagent in this case.
Good luck!
You just have to mix the two solutions (keep in mind that BaCl2 is toxic when ingested)
142.04 g Na2SO4 and 208,23 g BaCl2 yield 233.43 g BaSO4, so to obtain 1 g, you'll have to mix solutions that contain 0.608 (or 142.04/233.43) g Na2SO4 and 0.892 (or 208,23/233,43) g BaCl2. Please keep in mind that the dry salts may be hydrates (i.e. contain additional water), and then you have to recalculate the weights that you need.
As for limiting and excess reagents - if you add twice more Na2SO4 than given above to the amount of BaCl2 given above, you won't obtain 2 g of precipitate, and baCl2 is the limiting reagent in this case.
Good luck!