Chemistry Neutralization Reaction Question HELP

What volume of 0.730 mol/L H2SO4(aq) is required to completely neutralize 44.3 mL of 1.23 mol/L KOH(aq)?

H2SO4 + 2 KOH → K2SO4 + 2 H2O

(44.3 mL) x (1.23 mol/L KOH) x (1/2) / ( 0.730 mol/L H2SO4) = 37.3 mL H2SO4