Question about x and y intercepts? 10 points for help!

So my question is:

Find the x- and y-intercepts of the graph of the equation.
x = y^2 − 3

x-intercept(s) (x, y) =
y-intercept(s) (x, y) =

I'm doing this on the computer, and I have for the x int = (-3, 0)
and that's correct
But I don't know the part for y int =
(but it does tell me it involves two answers with the x values being 0?)

x = y^2 − 3
x-intercept(s)
y =0
x = -3
x-intercept(s) (x, y) = (-3,0) ---answer
y-intercept
x=0
y^2 − 3 =0
y = 1.732 and y = - 1.732
y-intercept(s) (x, y) = ( 0, 1.732) & ( 0, - 1.732)
answer

Just like you substitute y=0 for the y-intercept sub x=0 for the x-intercepts.
y^2 = x + 3 reordered to put y's on right side
y^2 = 0 + 3 sub x=0
y^2 = 3 simplify
y = = +/- square root 3 apply square root to both sides. There is a positive and negative answer.

put x=0 ; solve for value of y. that gives you the y intercept (0,y)
put y=0 ; solve for value of x. that gives you the x intercept (x,0)

for x-intercept put y=0 gives x=-3 (-3,0)
" y- ''''''''"""""""""""x=0 " y=+or-sqrt3, (0,+or-sqrt3)