During a physics experiment, a student pulls a rectangular conducting loop from between the poles of a magnet in 0.10s. The loop has an area of 8.0cm^2 and contains ten turns. Initially the entire loop is located in a region of uniform magnetic field of strength 0.1 T. The final position is free of the field.
What current flows through the loop in its original position? (Answer is 0 as it isn't being moved in its original position)
Calculate the average EMF induced in the loop by the student's action. (answer is 8.0 x 10^-3)
As you can see i understand how the answer to the first part of this question is found, but i can't figure out the second part, would anyone care to show me the process to find the answer? thank you very much in advance :)
What current flows through the loop in its original position? (Answer is 0 as it isn't being moved in its original position)
Calculate the average EMF induced in the loop by the student's action. (answer is 8.0 x 10^-3)
As you can see i understand how the answer to the first part of this question is found, but i can't figure out the second part, would anyone care to show me the process to find the answer? thank you very much in advance :)
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The EMF produced is E = -N d(phi) / dt where N is the number of turrns of the loop. here its 10.
phi is the magnetic flux which is nothing but the magnetic field times area. phi = B*Area= 0.1*8 cm^2 = 0.8 x 10^-4 m^2
Since we just need the average EMF, take the difference between starting and ending point.
E = N*(change in phi) /time difference = 10 * (phi -0 )/ 0.1 = 8 * 10 ^-3.
phi is the magnetic flux which is nothing but the magnetic field times area. phi = B*Area= 0.1*8 cm^2 = 0.8 x 10^-4 m^2
Since we just need the average EMF, take the difference between starting and ending point.
E = N*(change in phi) /time difference = 10 * (phi -0 )/ 0.1 = 8 * 10 ^-3.