The block of a mass 1.54869 kg has an acceleration of 2.6 m/s^2. There is a force pushing the block at an above of 27 degrees. What is the magnitude of the force? Assume acceleration due to gravity is 9.8 m/s^2 and the surface is frictionless. Answer in units of N.
Thank you ;)
Thank you ;)
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Since the surface is frictionless, you can just us F = MA, = 1.54869 x 2.6, = a horizontal component of 4.026594N.
Applied at an angle of 27 deg., (4.026594/cos27) = 4.51918N.
Applied at an angle of 27 deg., (4.026594/cos27) = 4.51918N.