What is the force on the block

There is two blocks (6kg and 4 kg) lined up with a 100N force coming from the right to the left.

What is the force on block 6?

[6][4] <--100N

I know the acceleration is 100N/10Kg = 10m/s^2. Would it just be 6x10 = 60N? Thanks for the help.

that is correct...the full analysis using newton's second law would look like this

consider all the forces on the 4 kg block; those are the 100N force to the left and the force of the 6kg block pushing on the 4 kg block

we write this as

100 - F6 = 4a where F6 is the force from the 6kg block and a is the acceleration of the system

for the 6kg block, the force acting on it is the force from the 4kg block, which we know from newton's third law is equal and opposite to the force on the 4 kg block, so we have

+ F6 = 6a

add these two equations:

100=10 a => a = 10m/s/s

if a=10m/s/s, then F6=60N