The coefficient of kinetic friction between the 2.0 kg block in figure and the table is 0.310

The coefficient of kinetic friction between the 2.0 kg block in figure and the table is 0.310. What is the acceleration of the 2kg block? Someone please help me and show me at least the steps, I cannot figure out how to do this at all.....

Here is a picture:
http://session.masteringphysics.com/prob…

The net force F acting on the system is the sum of 3 forces:
- the weight of the 1.0 kg block:
F1 = 1.0 x 9.8 = 9.8 N directed from right to left
- the friction force acting on the 2.0 kg block:
F2 = 0.310 x 2.0 x 9.8 = 6.1 N directed from right to left
- the weight of the 3.0 kg block:
F3 = 3.0 x 9.8 = 29.4 N directed from left to right

Then
F = 29.4 - 6.1 - 9.8 = 13.5 N from left to right

According to Newton's second law, the acceleration of the whole system (including the 2.0 kg block) is a = F / M, where F is the net force and M is the total mass of the system.

Therefore
a = 13.5 / (1.0 + 2.0 + 3.0) = 2.25 m/s² from left to right.