How come e^(iπ) is equal to -1

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How come e^(iπ) is equal to -1

[From: ] [author: ] [Date: 11-10-02] [Hit: ]

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Very complex, isn't it?

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Euler's identity, e^(i pi) +1=0

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e^(iπ)=cosπ + i sinπ = -1 + 0 = -1

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very punny

1

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