7. an elevator of mass 450 kg has an occupant of mass 150kg and is suspended from a cable. The elevator is initially at rest. assume g = 10 m/s^2
a. what is the total mass of the elevator and occupant?
b. what is the total weight of the elevator and occupant?
c. what is the magnitude tension in the supporting cable?
d. if the elevator and occupant are accelerating upward at a rate 2.5m/s^2, determine the magnitudeof the net force, the weight, and the tension in the supporting cable.
8. an object of mass m, resting on a horizonal frictionless surface is acted upon by an applied force F, the normal force of the surface Fn (same as N) and the gravitational force of the earth Fg (same as W) . Find Fg, Fn, and the acceleration of the object when
a. F = 15N and m = 2.0kg
b. F = 30 N and m = 2.0kg
c. F = 15 N and m = 1.0 kg
Please show work and the answer you were able to come up with your help is really appreciated you have no idea. My teacher cannot teach but will be giving a test on this tomorrow. Thanks so much to whoever can do this youre a life saver!
a. what is the total mass of the elevator and occupant?
b. what is the total weight of the elevator and occupant?
c. what is the magnitude tension in the supporting cable?
d. if the elevator and occupant are accelerating upward at a rate 2.5m/s^2, determine the magnitudeof the net force, the weight, and the tension in the supporting cable.
8. an object of mass m, resting on a horizonal frictionless surface is acted upon by an applied force F, the normal force of the surface Fn (same as N) and the gravitational force of the earth Fg (same as W) . Find Fg, Fn, and the acceleration of the object when
a. F = 15N and m = 2.0kg
b. F = 30 N and m = 2.0kg
c. F = 15 N and m = 1.0 kg
Please show work and the answer you were able to come up with your help is really appreciated you have no idea. My teacher cannot teach but will be giving a test on this tomorrow. Thanks so much to whoever can do this youre a life saver!
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7)
a] Masses add up, nothing tricky here. 600kg
b] Weight is simply the product of mass times local acceleration. weight = mg = 600kg*10m/s^2 = 6000N
c] Since the elevator is at rest there is a net balance of Forces. Weight is a force, so the magnitude of the tension in the wire is also 6000N.
d] To accelerate upwards at 2.5m/s^2, you are only interested in the net, or 'excess' force Think of it like F down = mg, F up = Tension. Then F net = mg + T + ma, where mg and T cancel each other so Fnet = ma = 600kg*2.5m/s^2. I am not positive about the last part due to a few beers, but - Weight should be the same (can't generate a net force otherwise), Tension however will increase and be T = ma + mg.
8)
a] Fg is always = mg = 2*10 = 20N. Fn = -Fg unless the object is moving up or down, so Fn = -20N.
Since F = 15N, F= ma, solve for a. a = F/m = 15/2 = 7.5m/s^2
b] Fg and Fn are the same here. acceleration is still a = F/m = 30/2 = 15m/s^2
c] Fg = mg = 1*10 = 10N, Fn = -Fg = -10N. a = F/m = 15m/s^2
a] Masses add up, nothing tricky here. 600kg
b] Weight is simply the product of mass times local acceleration. weight = mg = 600kg*10m/s^2 = 6000N
c] Since the elevator is at rest there is a net balance of Forces. Weight is a force, so the magnitude of the tension in the wire is also 6000N.
d] To accelerate upwards at 2.5m/s^2, you are only interested in the net, or 'excess' force Think of it like F down = mg, F up = Tension. Then F net = mg + T + ma, where mg and T cancel each other so Fnet = ma = 600kg*2.5m/s^2. I am not positive about the last part due to a few beers, but - Weight should be the same (can't generate a net force otherwise), Tension however will increase and be T = ma + mg.
8)
a] Fg is always = mg = 2*10 = 20N. Fn = -Fg unless the object is moving up or down, so Fn = -20N.
Since F = 15N, F= ma, solve for a. a = F/m = 15/2 = 7.5m/s^2
b] Fg and Fn are the same here. acceleration is still a = F/m = 30/2 = 15m/s^2
c] Fg = mg = 1*10 = 10N, Fn = -Fg = -10N. a = F/m = 15m/s^2