I need help with steps, I have no clue how to simplify the variables :
simplify : sqrt(27 x^9 y^3 z^5)
Like the x^9 would be x^3 I think but that's not in any of the answer choices , and what about y^3 and z^5 I know 27 would be 9 x 3 and 9 would turn to 3
simplify : sqrt(27 x^9 y^3 z^5)
Like the x^9 would be x^3 I think but that's not in any of the answer choices , and what about y^3 and z^5 I know 27 would be 9 x 3 and 9 would turn to 3
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CAREFUL
sqrt(16)=4..........Because 4 times 4 = 16
sqrt(X^16)does NOT equal x^4...........Since x^4 times x^4 equals x^8, not x^16
to take the square root of an EXPONENT you take half of it
sqrt(X^16)=x^8.................because X^8 times X^8 = X^(8+8) = x^16
sqrt(27 x^9 y^3 z^5)................find the largest EVEN number less than each of the odd exponents
sqrt(9x^8y^2z^4)sqrt(3xyz)
3x^4yz^2(sqrt(3xyz).................AN…
sqrt(16)=4..........Because 4 times 4 = 16
sqrt(X^16)does NOT equal x^4...........Since x^4 times x^4 equals x^8, not x^16
to take the square root of an EXPONENT you take half of it
sqrt(X^16)=x^8.................because X^8 times X^8 = X^(8+8) = x^16
sqrt(27 x^9 y^3 z^5)................find the largest EVEN number less than each of the odd exponents
sqrt(9x^8y^2z^4)sqrt(3xyz)
3x^4yz^2(sqrt(3xyz).................AN…
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To simplify a radical, find the perfect squares that are factors of the radicand. To find the square root of a variable, you have to divide it's exponent by 2, so leave one factor under the radical if it is odd.
sqrt(27 x^9 y^3 z^5)= SQR( 9*3*x^8*x*y^2*y*z^4*z)
= sqr[(9x^8*y^2*z*4)(3xyz)]
=3x^4yz^2*SQR(3xyz)
Hoping this helps!
sqrt(27 x^9 y^3 z^5)= SQR( 9*3*x^8*x*y^2*y*z^4*z)
= sqr[(9x^8*y^2*z*4)(3xyz)]
=3x^4yz^2*SQR(3xyz)
Hoping this helps!
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√(27x^9 y^3 z^5) = 3x^4 y z^2√(3xyz)
taking the square root is the same as raising to the (1/2) power
(x^9)^1/2 = x^4 * x^(1/2)
practice...
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taking the square root is the same as raising to the (1/2) power
(x^9)^1/2 = x^4 * x^(1/2)
practice...
¶