Permutations Help!!! PLS.pls.
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Permutations Help!!! PLS.pls.

[From: ] [author: ] [Date: 11-10-04] [Hit: ]
for that,then comes 3 S, so divide 10!/3!........
In how many ways the letters of the word SUCCESSFUL arranged?
In how many of them Ss will come together
Ss will not come together
S&U will come together

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1) answer- 151200
10 alphabets so 10! for that,then comes 3 S, so divide 10!/3!..then comes 2U so 10!/3!2! and the its 2 C so the final equation for this 10!/3!2!2!=151200
N.B. we have to divide the numbers that are repeated...there are 3S so we divide 3! ...2U thats y 2!

2)in this question think the 3 S as 1 unit,,,so this time we have 8 alphabets (7+1 unit that consists 3 S)...then go through like the previous one 8!/2!2!=10080

3)this is easy...151200-10080=141120

4)think the 5 as a unit here so we get 6 alphabets. so we can permute by 6!/2! and there is another catch we can permute the other 5(which we have considered here as 1 unit) by 5 5!/3!2! ...so the final answer is (6!/2!)*(5!/3!2!)=3600

for any further problem or explanation mail me @ arifaisal123@gmail.com
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