Prove that ∫ sin(i*x)/i dx = cosh(x) + C

[From: ] [author: ] [Date: 11-10-04] [Hit: ]

Hello,

sin(ix) / i = -i.sin(ix)
= sinh(x)

So:
∫ sin(i*x)/i dx = ∫ sinh(x).dx = cosh(x) + C

Logically,
Dragon.Jade :-)

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