Hi, my teacher doesn't teach us well. I direly need help I am in regular Chemistry. Can you explain and help me with these problems. I am stressing about the test tomorrow and it's not MULTIPLE CHOICE.
Thank you so much for answering! I need to maintain my straight A's and this class will break it for me. On the the problems:
Determine the mass of each of the following amounts:
a. 1.366 mol NH3
b. 0.120 mol glucose, C6H12O6
c. 6.94 mol barium chloride, BaCl2
d. 0.005 mol propane, C3H8
Don't need to answer them all if you don't want to first two would be fine please explain how to do these, I have no idea why I can't do these and I am a honor student in Math this should have came easy to me. THANKS again!
Thank you so much for answering! I need to maintain my straight A's and this class will break it for me. On the the problems:
Determine the mass of each of the following amounts:
a. 1.366 mol NH3
b. 0.120 mol glucose, C6H12O6
c. 6.94 mol barium chloride, BaCl2
d. 0.005 mol propane, C3H8
Don't need to answer them all if you don't want to first two would be fine please explain how to do these, I have no idea why I can't do these and I am a honor student in Math this should have came easy to me. THANKS again!
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a. (1.366 mol NH3) x (43.0281 g NH3/mol) = 58.78 g NH3
b. ( 0.120 mol C6H12O6) x (180.1566 g/mol) = 21.6 g glucose
c. (6.94 mol BaCl2) x (208.2341 g/mol) = 1.44 x 10^3 g BaCl2
d. (0.005 mol C3H8) x (44.0959 g/mol) = 0.2 g propane
b. ( 0.120 mol C6H12O6) x (180.1566 g/mol) = 21.6 g glucose
c. (6.94 mol BaCl2) x (208.2341 g/mol) = 1.44 x 10^3 g BaCl2
d. (0.005 mol C3H8) x (44.0959 g/mol) = 0.2 g propane