Mg (s) + HCl (aq) -> MgCl2 (aq) + H2 (g)
What mass of HCl is consumed by the reaction of 3.42 mol of magnesium?
Answer in units of g.
Okay. So first, I balanced the equation to Mg+2HCl -> MgCl2 + H2 and then idk what to do after that.
And then a follow up question is:
What mass of MgCl2 is produced. Answer in units of g.
What mass of HCl is consumed by the reaction of 3.42 mol of magnesium?
Answer in units of g.
Okay. So first, I balanced the equation to Mg+2HCl -> MgCl2 + H2 and then idk what to do after that.
And then a follow up question is:
What mass of MgCl2 is produced. Answer in units of g.
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Mg + 2 HCl → MgCl2 + H2
(3.42 mol Mg) x (2/1) x (36.4611 g HCl/mol) = 249 g HCl
(3.42 mol Mg) x (1/1) x (95.2115 g MgCl2/mol) = 326 g MgCl2
(3.42 mol Mg) x (2/1) x (36.4611 g HCl/mol) = 249 g HCl
(3.42 mol Mg) x (1/1) x (95.2115 g MgCl2/mol) = 326 g MgCl2