The combustion of ammonia in the presence of excess oxygen yields NO2 and H20:
4 NH3(g) + 7 O2(g) ---> 4 NO2(g) + 6 H2O(g)
The combustion of 28.8g of ammonia consumes _______ g of oxygen.
A)15.3 B)94.9 C)28.8 D)54.1 E)108
I have a test tomorrow and need to know how to do a problem like this. I got B)94.9 but am not sure that is correct. Verify for me please! Thanks!
4 NH3(g) + 7 O2(g) ---> 4 NO2(g) + 6 H2O(g)
The combustion of 28.8g of ammonia consumes _______ g of oxygen.
A)15.3 B)94.9 C)28.8 D)54.1 E)108
I have a test tomorrow and need to know how to do a problem like this. I got B)94.9 but am not sure that is correct. Verify for me please! Thanks!
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4 NH3 + 7 O2 → 4 NO2 + 6 H2O
(28.8 g NH3) / (17.0306 g NH3/mol) x (7/4) x (31.9989 g O2/mol) = 94.7 g O2
You are correct.
(28.8 g NH3) / (17.0306 g NH3/mol) x (7/4) x (31.9989 g O2/mol) = 94.7 g O2
You are correct.