http://www.admissionstests.cambridgeasse…
It's question 5
if he has grandchildren, and there's atleast ONE BIRTHDAY in each month
minimum = 12
but he has 5 pairs of twins
3 of them having birthdays in april
but one is counted so 5
112+5 = 17
he then has four kids / 2 twins, ASSUMING each is counted already, this is two more
= 19
but i'm wrong?
It's question 5
if he has grandchildren, and there's atleast ONE BIRTHDAY in each month
minimum = 12
but he has 5 pairs of twins
3 of them having birthdays in april
but one is counted so 5
112+5 = 17
he then has four kids / 2 twins, ASSUMING each is counted already, this is two more
= 19
but i'm wrong?
-
6 kids in April, 2 other sets of twins (let's assume they're in 2 different months), 9 months left over
6 + 4 + 9 = at least 19, so far
Twice as many females as males, so the number must be divisible by 3 (2/3 female, 1/3 male). The smallest number greater than 19 that's divisible by 3 is 21. E
6 + 4 + 9 = at least 19, so far
Twice as many females as males, so the number must be divisible by 3 (2/3 female, 1/3 male). The smallest number greater than 19 that's divisible by 3 is 21. E