Point A [3, -1] and B [-5, K]
The line AB has equation y=5-2x
For this i subbed in -5 to the equation and found that y = 15 but then i remembered that to find y, x had to equal 0? but i think i may be abit confused there.. can anyone help?
The line AB has equation y=5-2x
For this i subbed in -5 to the equation and found that y = 15 but then i remembered that to find y, x had to equal 0? but i think i may be abit confused there.. can anyone help?
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y = -2x + 5
the slope of the line is -2
(K - (-1)) / (-5 - 3) = -2
(K + 1) / -8 = -2
K + 1 = 16
K = 15
B[-5, 15]
the slope of the line is -2
(K - (-1)) / (-5 - 3) = -2
(K + 1) / -8 = -2
K + 1 = 16
K = 15
B[-5, 15]
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pretty certain that you are right about y=K=15, because you have the equation of the line already so you should be able to plug any value in and get the other part of any given point