Help on a math problem please

Explain how you got your answer please.

1) Find the equation of the line in slope-intercept form that is parallel to the line 2x+y= -5 and contains the point (3, -1)

Thanks everyone.

I got 2x+y=5 but i'm not sure if that is correct.

rearrange your original equation to give it in the format y = mx + b
2x+y= -5
y = -2x -5

If the line is parallel the slope must be the same, so -2x remains the same

y = -2x + b
you know that y = -1 and x = 3

-1 = -2*3 + b
-1 = -6 + b
-1 + 6 = b
5 = b

y = -2x +5
2x + y = 5

You would be correct, but the question calls for it to be in slope intercept form, so the answer must be in the form y = mx + b

So the answer is y = -2x + 5