Grade 8 Math question

How do you solve this? XD
Lang withdrew half of his money from his bank account on the last day of January. Then he withdrew half of the remaining amount on the last day of February. He continued withdrawing half of the remaining amount on the last day March, April, May, and June. His final balance was $1.50. How much money did Lang have in his bank account before his first withdrawal.

June1.5+1.5=3
may3+3=x
apr x+x=y
mar y+y=z
feb z+z=a
jan a+a=the answer

Well, you can work backward - if he ended with 1.50, before his last withdrawl he had 3. Go backward doubling it for each month (but don't lose count!)

Or you can set up the equation like this:

Let x = starting amount
Each withdrawl multiplied x by 1/2
x * (1/2)^6 = 1.5
(1/2)^6 = 1/64
x/64 = 1.5

I bet you can finish it from there.

he had x originally
after withdrawing in january he had x/2,
after feb, x/2/2 = x/4
after march, x/4/2 = x/8 etc
..
after the june withdrawal he had x/(2^6) = x/64

x/64 = $1.50
x = $1.50 * 64 = $96

Well you go backwards. So start with 1.50 then x that by 2 since Lang took half so that's 3 then double that and keep doubling your product 3 more times because of how many times he took half and you answer is 96.

1.50 x 6 lol thats some easy sh!t... Lol trust me its the right answer... Good luck playboy