Calculate the derivative of g(x)=(x^2+4x^1/2)/x^2
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Calculate the derivative of g(x)=(x^2+4x^1/2)/x^2

[From: ] [author: ] [Date: 12-09-20] [Hit: ]
......
The answer is -6x^-5/2 but I don't know how to get it!

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g(x) = (x^2 + 4x^(1/2))/x^2 = distributive law

= x^2/x^2 + 4x^(1/2)/x^2 =

= 1 + 4 x^(1/2 - 2) =

= 1 + 4x^(-3/2)

g'(x) = 4·(-3/2) x^(-3/2 - 1)

g'(x) = - 6x^(-5/2) = - 6/(x²√x)

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just plug it into www.wolframalpha.com
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